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Old 04-01-2008   #51
J()e
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Default Re: MATHS riddle

Here is the solution

Why it is impossible here it goes:

as we said everyday we must kill a number impair(mefrid)of cows

and we know enno impair+impair=pair for example(3+3=6 6=pair while 3=impair,7+7=14 etc....)

so in every 2 days we have a number pair of cows that are going to die
in 4 days we have also a number pair
but in the 5th day we have an impair number while the number desired to be reached is 30 wich is pair cause 30 can be divided by 2


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Old 04-01-2008   #52
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Default Re: MATHS riddle

joe the sum of 5 odd numbers MUST be an odd number
(2n+1)*5 = 10n+5. knowing 10n is even(multiple of 2), and adding 5, we can tell that the result is odd.
starting from the fact that 0 is not an odd number, you cannot have 5 odd numbers who sum up to 30. i dunno why u guys even tried finding the answer
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Old 04-01-2008   #53
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Default Re: MATHS riddle

Tayeb Tayeb inta w yeh yala more riddles,shu ba3mel i 4got skool days
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Old 04-01-2008   #54
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Default Re: MATHS riddle

i wanna know abt my answer to alias' riddle! i sent him a pm a while ago. mafroud enno i got it right!
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Old 04-02-2008   #55
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Default Re: MATHS riddle

sorry i didn't reply sooner
my internet was down... but now it is working again

duce and crystal soul got it right

the answer is:
5 cigs
how?
well he has 10
10= 9+1
from the 9 he makes 3 cigs
he smokes them and each cig produces a leftover
now he has 3(from smoked cigs) and 1(from the original 10)
so with the 3 he makes a cig and smokes it and so he get another leftover
so now he has 2
he borrows 1 from his friend
now he has 3
he makes them a cig and smoke it and get from it 1 leftover
so he returns it to his friend
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Old 04-02-2008   #56
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Default Re: MATHS riddle

yalla more riddles guyz...try to post here

we need riddles to solve
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Old 04-02-2008   #57
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Default Re: MATHS riddle

here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....
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Old 04-02-2008   #58
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Default Re: MATHS riddle

Quote:
Originally Posted by J()e View Post
here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....


The Time when 1 of them return byen7asab mn l 17 minutes?
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Old 04-02-2008   #59
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Default Re: MATHS riddle

of course....

it's easy yalla

PS:if for example the 2nd and the 1st crossed the bridge bten7asab 2 mins Raw7a.
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Old 04-02-2008   #60
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Default Re: MATHS riddle

Quote:
Originally Posted by ALIAS View Post
abousoun gest it 90% right
he got the total rights but he made 1 mistake he broke the second rulebass bi tari2a gher moubashara - yemkem el rule ma kenet wad7a mazbout)

he can only borrow one (and only one) from one friend (only one friend) (i think it is clear now)
i will post the solution tomorrow noon unless you want more time to think about it
you said frist borrow one cigarette from a friend, not one cigarette from one friend ... heik byi5telif, otherwise why he would have many friends in this ridle, one friend bzyede

Quote:
Originally Posted by J()o
here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....
PM sent, w concerning your previous riddle ... there was no connection to send the answer

Thank You ...
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