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**Tawa** · 12-03-2008

Code:

int x, y;
char z;
 
cin >> x;
while(1){
   cin >> z;
   if(z != '+' && z != '-')
       break;
   cin >> y;
   if(z == '+')
       x+=y;
   else if(z == '-')
       x-=y;
}
if(z != '=')
    cout << "Syntax Error" << endl;
else
    cout << "The Result Is: " << x << endl;

This Should Do The Work.

12-03-2008	#5
Tawa  Last Online: 12-20-2021 Join Date: Mar 2006 Posts: 6,245 Thanks: 2,121 Thanked 3,365 Times in 1,740 Posts Groans: 29 Groaned at 44 Times in 35 Posts	Re: c++ guru, urgent plz Code: int x, y; char z; cin >> x; while(1){ cin >> z; if(z != '+' && z != '-') break; cin >> y; if(z == '+') x+=y; else if(z == '-') x-=y; } if(z != '=') cout << "Syntax Error" << endl; else cout << "The Result Is: " << x << endl; This Should Do The Work. __________________ What we do in life, echoes in eternity.