[mitain]

Originally Posted by xcoder

Hello guys i need your support in my studies from time to time so please keep this thread for this. Please no meaningless replies i really need to make it this year.
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Interets Composes:

Un capital de 4500000 LL est place, a interets composes au taux de 10.5% pendant 4 ans. Trouver la valeur acquise.

Solution:

Capital (c) = 4500 000
Interet(I) = 1 LL x 10,5% = 0,105
Duree (n) = 4 ans
Valeur acquise = Capital + Interets

La formule generale est:

A= C(1+I)4
A= 4.500.000(1,105)4

Log(A) = log(4.500.000) + 4 X log(1,105)
Log(A) = 6,653.21 + (4 x 0,04336)
Log(A) = 6,826.65
A = 6.708.880 LL

I knew how it all works but i couldn't know from where we got the result i reached (Log(A) = 6,826.65) and 3ela2et.

man hayda math finiance , lek chou esme al ketaib li betdross fi !!!!