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Old 06-28-2008   #11
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Default Re: Hacking Password 4

Till now only Kingroudy, polo, joseph28 and xcoder solved this challenge...
And only xcoder solved it using the easiest way


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Old 06-28-2008   #12
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Default Re: Hacking Password 4

Dooooone and the pass is :"F17D2587068A7515F97A928C13E71690"

Last edited by Dr.Scoo; 06-28-2008 at 11:46 AM.
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Old 06-28-2008   #13
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Default Re: Hacking Password 4

wlak i wasted all my time and javascript was disabled on firefox
loooooooooooooooooooooooooool
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Old 06-28-2008   #14
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Default Re: Hacking Password 4

Quote:
Originally Posted by Kingroudy View Post
wlak i wasted all my time and javascript was disabled on firefox
loooooooooooooooooooooooooool
kif 2el javascript was disabled w 2deret ta3mel 2el challanege ???
Kif shtaglet ma3ak 2el check button then ???
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Old 06-28-2008   #15
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Default Re: Hacking Password 4

okey i was googling to find out what a line means in the source text
and i came accross the solution ... although i didn't understand anything
so it took me less than a minute to solve it , since the search result only had 1 page ... copy / paste and i'm done
waiting to read the solution

Thank You ...
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Last edited by abousoun; 06-28-2008 at 01:31 PM.
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Old 06-28-2008   #16
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Default Re: Hacking Password 4

lol abousoun you're such a cheater, even when it comes to quizzes
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Old 06-28-2008   #17
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Default Re: Hacking Password 4

Quote:
Originally Posted by 454447415244 View Post
kif 2el javascript was disabled w 2deret ta3mel 2el challanege ???
Kif shtaglet ma3ak 2el check button then ???
i use 2 browsers (opera and mozilla firefox)
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Old 06-29-2008   #18
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Default Re: Hacking Password 4

Done
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Old 06-29-2008   #19
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Default Re: Hacking Password 4

Done!!!!!!!!!, but the hard way
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Old 07-01-2008   #20
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Default Re: Hacking Password 4

The persons who solved this challenge are:
Kingroudy, polo, joseph28, xcoder, Dr.Scoo, abousoun, Rami_s and chaingang_100.


we can solve this challenge in two ways...
Either we do some hard calculations or we just do it in a very easy way...

First method:


The funcion unescape converts the hex value to ascii code...
so "%61%68%6f%79" will be "ahoy" (61=a ; 68=h ; 6f=o ; 79=y)...
The string "ahoy" is assigned to the variable rawr...

The function charCodeAt(integer number) convert a ascii character to decimal number...
It depends on the input, first we are writing "string.function" which means that we are going
to apply this function on the variable called "string"... Second thing to know is that
we are giving the function an input, for example: string.charCodeAt(1); ... the input is one...
So the function "charCodeAt" is going to check the second character of the variable "string"...
In javascript and in other programming languages, we begin counting from 0, which means that the

number 2 is the third... (we have 0,1,2,3,4...ect..)
The second character is "l" and it is 108 in decimal (using a ascii to decimal convertor)...
The number 108 is assigned to the variable a.
The 8'th character is also "l"...
The number 108 is assigned to the variable b.
The 5'th character is "a" and it is 97 in decimal.
The number 97 is assigned to the variable c.
Note that we can check the numbers...by pressing the key alt+97 we obtain the letter a.

Now we have to do some calculations in order to obtain the value of the variable schloob...
Note that in the calculation, the priority is for the multiplication and the division...
So at the end, we divide by 2 then we divide by 5 and not 5+b... after we divide by 5 we add b to

the whole...
we sould obtain the number 9860.4 ...

now, asdf=rawr+"_"+schloob; is telling us to assemble our variables and put "_" between them...
So the password will be ahoy_9860.4

Second method:
We can just add to the code:
document.write(asdf);

or alert(asdf);
or put asdf in the place of "
'Shame on you!!!'"


That's all...

I hope you enjoyed this tutorial :P





Last edited by Google; 07-01-2008 at 01:15 PM.
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