MATHS riddle

[duce]

abousoun i pm'd u AN answer... still have 2 check if it's correct

[abousoun]

Till now :
- Concerning the Tomato's riddle Tawa is the first one to answer it right
- Concerning Sweets_HsN phone number riddle enigma the third one to solve it (added to Joe and Crystal Soul)

P.S : - I'll post the answer on Sunday since tomorrow i won't be available
- Remember that the 12 balls riddle is still in the game

Thank You ...

[J()e]

abousoun i sent an answer concering the tomato one...it was really easy badda 'foten':P:P
yalla a new riddle:
Sweets_HSN is 2e3id bi 2ouda...bhal 2ouda fi 3 kabset kermel ydawe el daw,wel daw barrat el 2ouda,bi 7e2elo yotla3 marra we7de mn 2el 2ouda..kirmel ychouf iza dawa el daw....and he can press kbasten at the same time!!

can any1 help sweets_HSN ya3rif ayya kabse bet dawe el daw???

[MORPHEUSP]

abousoun ayya 12 balls riddle can you repost it plz cz morhpeus has just entered the game :P

[Tawa]

Originally Posted by MORPHEUSP

abousoun ayya 12 balls riddle can you repost it plz cz morhpeus has just entered the game :P

Go To The 22th Post In This Thread
Click Here

[J()e]

lhay2a crystal soul got was the 1st to help sweets_HSN ydawe el daw..

who is the 2nd??

c'on is very easy

[Tawa]

Originally Posted by J()e

lhay2a crystal soul got was the 1st to help sweets_HSN ydawe el daw..

who is the 2nd??

c'on is very easy

The Switch?

[J()e]

The queen is the 2nd winner...mn ba3ed crystal soul.

[abousoun]

Sweets_HsN phone number Riddle answer:

Let's start by using divisibility rules to list the restrictions
imposed by the conditions of the problem....
The number formed by the first digit is divisible by 1
(there are no restrictions imposed by this condition since every
1-digit number is divisible by 1)
The number formed by the first two digits is divisible by 2
(1) digit 2 must be even
The number formed by the first three digits must be divisible by 3
(2) the sum of digits 1-3 must be divisible by 3
The number formed by the first four digits must be divisible by 4
(3) digit 4 must be even
(4) the number formed by digits 3-4 must be divisible by 4
The number formed by the first five digits must be divisible by 5
(5) digit 5 must be 5
The number formed by the first six digits must be divisible by 6
(6) digit 6 must be even
(7) the sum of digits 1-6 must be divisible by 3
The number formed by the first seven digits must be divisible by 7
(rules for divisibility by 7 are clumsy - let's not try to impose
any restrictions on the digits here...)
The number formed by the first eight digits must be divisible by 8
(8) digit 8 must be even
(9) the number formed by digits 6-8 must be divisible by 8
The number formed by the first nine digits must be divisible by 9
(10) the sum of digits 1-9 must be divisible by 3

Now let's start combining these restrictions logically to try to
determine some of the digits.
From (1), (3), (6), and (8) above, digits 2, 4, 6, and 8 are even; so
(11) digits 1, 3, 7, and 9 are odd (we already know digit 5 is odd)
From (2), (7), and (10) above, the sum of digits 1-3, the sum of
digits 1-6, and the sum of digits 1-9 are all divisible by 3; from
this, we can conclude that
(12) the sum of digits 4-6 is divisible by 3
(13) the sum of digits 7-9 is divisible by 3
From (1) and (11) above, digits 1-3 are odd, even, and odd; their sum
is therefore even. From (2), this sum is divisible by 3. Therefore
(14) the sum of digits 1-3 is an even multiple of 3 (6, 12, 18,
or 24)
From (3), (5), and (6) above, digits 4-6 are even, odd, and even;
their sum is therefore odd. From (12), this sum is divisible by 3.
Therefore
(15) the sum of digits 4-6 is an odd multiple of 3 (9, 15, or 21)
From (8) and (11) above, digits 7-9 are odd, even, and odd; their sum
is therefore even. From (13), this sum is divisible by 3. Therefore
(16) the sum of digits 7-9 is an even multiple of 3 (6, 12, 18,
or 24)
From (15), the sum of digits 4-6 is either 9, 15, or 21; and from (5)
we know digit 5 is 5. From (3) and (6), digits 4 and 6 are different
even numbers. These facts together give us only a small number of
possible combinations for digits 4-6:
(17) the only possibilities for digits 4-6 are 258, 852, 456,
and 654
From (4) and (11), digits 3-4 form a 2-digit number with first digit
odd that is a multiple of 4. With digit 3 odd, we then know
(18) the only possibilities for digit 4 are 2 and 6
Combining (17) and (18), we now have
(19) the only possibilities for digits 4-6 are 258 and 654
From (8), (9), and (11), digits 6-8 form a 3-digit number, divisible
by 8, with middle digit odd. We can combine this with (19) to
determine
(20) if digits 4-6 are 258, then digit 8 must be 6, making digit 2
equal to 4
(21) if digits 4-6 are 654, then digit 8 must be 2, making digit 2
equal to 8
From (1), (11), and (14), digits 1-3 are odd, even, and odd, and the
sum of those digits is an even multiple of 3. Here is a complete list
of the possibilities for these digits:
(sum = 6) 123 321
(sum = 12) 129 921 327 723 147 741 183 381
(sum = 18) 729 927 369 963 189 981 387 783
(sum = 24) 789 987
From (20), we know that if digits 4-6 are 258, then digit 8 must be 6,
making digit 2 equal to 4. In the list of possible combinations for
digits 1-3, there are only two combinations with digit 2 equal to 4
(147 and 741); so we now know that
(22) if digits 4-6 are 258, then the possible solutions to the
problem are
147 258 369 or 147 258 963
741 258 369 or 741 258 963
With these possible solutions, digits 6-8 are either 836 or 896;
condition (9) eliminates the two possible solutions with digits 6-8
equal to 836. Then, the requirement that the number formed from
digits 1-7 be divisible by 7 eliminates the two possible solutions
with digits 6-8 equal to 896. So there are no solutions with digits
4-6 equal to 258.
From (21), we know that if digits 4-6 are 654, then digit 8 must be 2,
making digit 2 equal to 8. In the list of possible combinations for
digits 1-3, there are eight combinations with digit 2 equal to 8; this
tells us that
(23) if digits 4-6 are 654, then the possible solutions to the
problem are
183 654 729 or 183 654 927
381 654 729 or 381 654 927
189 654 327 or 189 654 723
981 654 327 or 981 654 723
387 654 129 or 387 654 921
783 654 129 or 783 654 921
789 654 123 or 789 654 321
987 654 123 or 987 654 321
With these possible solutions, digits 6-8 are either 412, 432, 472,
or 492; condition (9) eliminates the possible solutions with digits
6-8 equal to either 412 or 492. The remaining possible solutions are
183 654 729
381 654 729
189 654 327
981 654 327
189 654 723
981 654 723
789 654 321
897 654 321
Only one of these satisfies the condition that the number formed by
digits 1-7 be divisible by 7.
The single solution to the problem is
381654729

Winners : J()e, Crystal Soul , enigma ...

Thank You ...

[Sogelec]

Originally Posted by abousoun

Sweets_HsN phone number Riddle answer:
The single solution to the problem is
381654729

Winners : J()e, Crystal Soul , enigma ...

Thank You ...

OMG, walaw ya Abousoun Mneen Bado Ye7faz J()e hal Number