MATHS riddle

[J()e]

Geometric maths riddle:

fi 3inna hal triangle:

with A point fixe M and N are 2 pts variables (not fixe)

we have enno AM/AN=cte
the angle formed bye [NA,AM]=cte

chou howeh the geometric location for N if M btet7arrak 3ala el droite (AM)

answer by pm

ps:ejetna bl saff w i was the 1st one to solve it mish enno ana yaba aw chi

[Tawa]

Originally Posted by J()e

2nd winner:

Tawa w 7alla mitl el 3ade 3al C++ wa7esh ya tawa

he'll post his answer later.

#include <iostream>
 using namespace std;

  #define MAX 1000000
 int Reverse(int);

  void main(void)
{
    for(int i = 0; i < MAX; i++)
        if(2*i-1 == Reverse(i))
            cout << "Matching Number: " << i << " / " << Reverse(i) << endl;
}

  int Reverse(int a)
{
    int b = 0;
    while(a > 0)
    {
        b *= 10;
        b += a%10;
        a /= 10;
    }
    return b;
}

I Love C++, Keep Them Coming Guyz

[J()e]

1st winner abousoun.

[Sogelec]

I Dont Know Geometry, lol while i was in School i did SE, and the Last Time I Took Such Geometry was in Grade 10
so i dnt knw J()e if you meant by the Geometric location = the Locus
ill try 2 think of it, bas a really new topic
Da5lkon Tawa ma 3emel Program to Solve it

[abousoun]

A new Riddle :
Crystal Soul is trying to decode Sweets_HsN password:
1 - his password is composed of 5 numbers
2 - the 4th # is more than the 2nd # by 4
3 - the 3rd # is less than the 2nd # by 3
4 - the 5th # is 3 times less than the 1st #
5 - there is 3 combinations of 2 numbers where their sum will be 11

to explain the last point ya3ne if the number is abcde :
we have (a + b = 11), (c + d= 11), (a+e = 11)
or (a + c = 11), (c + e = 11), (d + e = 11)
etc ....

Can you help Crystal Soul to decode Sweets_HsN password ?

P.S : it can be solved without a C++ program , but such solutions are acceptable

Thank You ...

[abousoun]

chou wein el sha3b ???? ... Sweets_HsN password Riddle is a very easy one and shouldn't take more than 5 or 10 minutes ...

Thank You ...

[abousoun]

ezzahir nafa3 my encouragement
enigma first one to crack the password ... bravoooo

Thank You ...

[abousoun]

Answer of Sweets_HsN Password Riddle:

as per given conditions, there are three possible combinations for 2nd, 3rd and 4th #. They are (3, 0, 7) or (4, 1, 8) or (5, 2, 9)

It is given that there are 3 combinations of two # whose sum is 11. All possible pairs are (2, 9), (3, 8), (4, 7), (5, 6).

Now required number is 5 digit number and it contains 3 pairs of 11. So it must not be having 0 and 1 in it.

Hence, the only possible combination for 2nd, 3rd and 4th digits is (5, 2, 9)

Also, 1st digit is 3 times the last digit. The possible combinations are (3, 1), (6, 2) and (9, 3), out of which only (6, 2) with (5, 2, 9) gives 3 pairs of 11. Hence, the answer is 65292.

Winner : enigma

Thank You ...

[abousoun]

New Riddle:
Tawa and enigma met after a long time ...
now Tawa have 3 sons machalla ...
so enigma asked how old are they ?
Tawa replied : if i multiply the ages of my 3 sons, it will be 36
enigma said : I still don't know
so Tawa look around and then replied : if i add the ages of my 3 sons, it will be the sameas the numbers of cars on this side of street ...
enigma replied : Come on Tawa , i still needs more than that to know
so Tawa said : my eldest son looks exactly like me
then enigma knew the ages of his sons

now can you know ?

Thank You ...

[abousoun]

enigma first one to solve Tawa's sons ages Riddle

El-Meghwar got it as well

Jess ndammit la enigma w El-Meghwar

- J()e and Crystal Soul solved it too

Thank You ...