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#201 |
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1st winner : J()e sarle 10 mins posted the riddle walaw ntor chwey ![]() 2nd winner : Sweets_HsN
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If my smoking bothers you. Don't breathe. ![]() Last edited by Jess; 05-03-2008 at 11:56 PM. |
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#202 |
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The winners are: J()e, Sweets_HsN and Tawa
![]() The Answer :X is Abousoun's age. Y is his wife's age. y - x = x/11 + y/11 y - y/11 = x + x/11 10y/11 = 12x/11 y = 1.2x y = 10a + b x = 10b + a 10a + b = 12b +1.2a 8.8a = 11b a = 1.25b Two digits that satisfy this are: a = 5 b = 4 x = 45 <-- Abousoun's age y = 54
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If my smoking bothers you. Don't breathe. ![]() |
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#203 |
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Tawa spent one-fourth of his life as a boy, one-eighth as a youth, and one-half as an active man. If Tawa spend spent 12 years as an old man, then how many years did he spend as an active man?
pm me the answer
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#204 |
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Weinkon ya jame3a
![]() Btw the riddle is ranked as an easy one. in the mean time think of this: ![]() In the above figure, the rectangle at the corner measures 5 cm x 10 cm. What is the radius of the circle in cm?
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#205 |
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1st winner on tawa's riddle:
Sweets_hsn
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| The Following User Says Thank You to J()e For This Useful Post: | Sogelec (05-07-2008) |
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#206 |
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sweets_hsn solved the 2nd circus riddle
![]() Bravo
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| The Following User Says Thank You to J()e For This Useful Post: | Sogelec (05-07-2008) |
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#207 |
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enigma solved the circle riddle
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#208 |
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tawa's riddle solution:
Fraction of life as a boy = 1/4 Fraction of life as a youth = 1/8 Fraction of life as an active man = 1/2 Fraction of life as boy, youth and active man = 1/4 + 1/8 + 1/2 = (2 + 1 + 4)/8 = 7/8 Fraction of life as an old man = 1 − 7/8 = 1/8 Thus, one-eighth of Tawa's life (as an old man) is 9 years. So, Tawa's Age = 72 years. It may be noted that: Life as boy = 72/4 = 18 years. Life as youth = 72/8 = 9 years. Life as active man = 72/2 = 36 years. The radius of the circle riddle: ![]() Using Pythagoras' Theorem (see Hint above) for the right-angled triangle in the figure alongside, (r - a)2 + (r - b)2 = r2 Now, a = 5 cm and b = 10 cm. So, (r - 5)2 + (r - 10)2 = r2 or r2 - 2(5)r + 52 + r2 - 2(10)r + 102 = r2. This simplifies to r2 - 30r + 125 = 0. On factorizing, we get (r - 25)(r - 5) = 0. Thus, the radius of the circle is 25 cm. Food for thought: In the above solution, (r - 25)(r - 5) = 0. Thus, r = 25 cm. The other possibility (r = 5 cm) is rejected. Why? Is the following reasoning valid? r - b = 5 - 10 = -5 cm. No negative dimension is allowed.
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| The Following User Says Thank You to J()e For This Useful Post: | Sogelec (05-11-2008) |
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J()e was Watching TV, Since Breaking News are Many and He Wants to Be Up to Date with da news
J()e was Sad, His Prom might Vanish Away, When Tawa Called!!! Tawa was Burning a Tire, and he Sat Down a Little Bit, when his Friend Asked him a Riddle; if He Answers Correctly He Will be Able to Shoot a B7 Into the Saray, that was Tawa's Dream the Riddle Says; there is a Number, if we Add its Digits, and then multiply them by 8, we will get the Same #. Tawa was Busy with the Tires, so J()e was his only Math Hero. Awaitin You Answers...By PM
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Crystal Soul Solved it, with a "
"J()e Solved it kamen, with a " "Last edited by Sogelec; 05-11-2008 at 04:35 PM. |
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| The Following User Says Thank You to Sogelec For This Useful Post: | Crystal Soul (05-11-2008) |
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