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Old 05-03-2008   #201
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Default Re: MATHS riddle

1st winner : J()e sarle 10 mins posted the riddle walaw ntor chwey

2nd winner : Sweets_HsN



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Old 05-04-2008   #202
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Default Re: MATHS riddle

The winners are: J()e, Sweets_HsN and Tawa

The Answer :

X is Abousoun's age.
Y is his wife's age.

y - x = x/11 + y/11

y - y/11 = x + x/11

10y/11 = 12x/11

y = 1.2x

y = 10a + b

x = 10b + a

10a + b = 12b +1.2a

8.8a = 11b

a = 1.25b

Two digits that satisfy this are:
a = 5
b = 4

x = 45 <-- Abousoun's age
y = 54
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Old 05-06-2008   #203
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Default Re: MATHS riddle

Tawa spent one-fourth of his life as a boy, one-eighth as a youth, and one-half as an active man. If Tawa spend spent 12 years as an old man, then how many years did he spend as an active man?

pm me the answer
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Old 05-06-2008   #204
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Default Re: MATHS riddle

Weinkon ya jame3a

Btw the riddle is ranked as an easy one.

in the mean time think of this:



In the above figure, the rectangle at the corner measures 5 cm x 10 cm. What is the radius of the circle in cm?
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Old 05-07-2008   #205
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Default Re: MATHS riddle

1st winner on tawa's riddle:

Sweets_hsn
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Old 05-07-2008   #206
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Default Re: MATHS riddle

sweets_hsn solved the 2nd circus riddle

Bravo
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Old 05-07-2008   #207
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Default Re: MATHS riddle

enigma solved the circle riddle
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Old 05-11-2008   #208
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Default Re: MATHS riddle

tawa's riddle solution:

Fraction of life as a boy = 1/4
Fraction of life as a youth = 1/8
Fraction of life as an active man = 1/2
Fraction of life as boy, youth and active man = 1/4 + 1/8 + 1/2 = (2 + 1 + 4)/8 = 7/8
Fraction of life as an old man = 1 − 7/8 = 1/8
Thus, one-eighth of Tawa's life (as an old man) is 9 years.
So, Tawa's Age = 72 years.

It may be noted that:
Life as boy = 72/4 = 18 years.
Life as youth = 72/8 = 9 years.
Life as active man = 72/2 = 36 years.


The radius of the circle riddle:



Using Pythagoras' Theorem (see Hint above)
for the right-angled triangle in the figure alongside,
(r - a)2 + (r - b)2 = r2
Now, a = 5 cm and b = 10 cm. So,
(r - 5)2 + (r - 10)2 = r2 or
r2 - 2(5)r + 52 + r2 - 2(10)r + 102 = r2. This simplifies to
r2 - 30r + 125 = 0. On factorizing, we get
(r - 25)(r - 5) = 0.
Thus, the radius of the circle is 25 cm.

Food for thought:
In the above solution,
(r - 25)(r - 5) = 0.
Thus, r = 25 cm. The other possibility (r = 5 cm) is rejected. Why?

Is the following reasoning valid?
r - b = 5 - 10 = -5 cm. No negative dimension is allowed.
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Old 05-11-2008   #209
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Default Re: MATHS riddle

J()e was Watching TV, Since Breaking News are Many and He Wants to Be Up to Date with da news
J()e was Sad, His Prom might Vanish Away, When Tawa Called!!!
Tawa was Burning a Tire, and he Sat Down a Little Bit, when his Friend Asked him a Riddle; if He Answers Correctly He Will be Able to Shoot a B7 Into the Saray, that was Tawa's Dream
the Riddle Says; there is a Number, if we Add its Digits, and then multiply them by 8, we will get the Same #.
Tawa was Busy with the Tires, so J()e was his only Math Hero.


Awaitin You Answers...By PM
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Old 05-11-2008   #210
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Default Re: MATHS riddle

Crystal Soul Solved it, with a ""
J()e Solved it kamen, with a ""

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