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#21 |
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Here's my Final term phisics test ... for Life Science and General Science Students ... hit it Joe
... and if ur intrested ill scan other subjects like Chemistry, Math, History finals thx .... ![]() ![]() ![]()
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“Please dnt call me arrogant,but Im European champion & I think Im a special one." Jose Mourinho
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#22 |
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Bitarno ill give an easy way to study philo, history, geo, w tarbiya...listen buy annal "chamel" u must have it, look to all the previous sessions for all sections (eza elak khele2 la keloun
) read the quest w memorize their answers... u'll pass these courses believe me cz same questions ma fi chi jdid 3a "mar sinin" :P eno im tellin u that based on my exp ![]() Gd luck
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Dima.M |
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#23 |
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yalla #1 is solved
10x man zakkartne fion ![]() ![]() ![]() yalla workin on the 2nd one bass haida baddak tontor cz fi match germany ![]() ![]() bass chaghle: bl partie i-c) fi kelmeh ma2touche hiyyeh "sombre" aw obscur
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[ Last edited by J()e; 06-08-2008 at 07:22 PM. |
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| The Following User Says Thank You to J()e For This Useful Post: | bitarno (06-08-2008) |
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#24 |
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JOE ur officially Geek
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#25 |
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II
1-quantized: it can't take any "valeurs" 2-cz they are under E (infinity)=0 therefore everything beneath it is negative 3-Eph (5-->2)=E(5)-E(2)= -1.51+3.54=2.03 eV Eph=hc/ ч =2.03X1.6x10^-19=3.248*10^-19 --> ч =hc/3.248*10^-19 --> ч =6*10^-7 m 4-a)E(2)-E(1)=1.89ev b)E(infinity)-E(1)=5.39ev 5-here we calculate Eph1 and Eph2 w mn chouf iza chi we7de mennon correspond a la difference de 2 transitions: Eph1=(hc/ ч1)*1.6*10^-19=3.8ev or ma3na enno E(5)-E(1)=3.8 Hence => ч=323*10^-9m can be absorbed 5- el electron fi yenzal mn 3ŕ1 3ŕ2 2ŕ3 Max wave length equals the transition 2ŕ1 Hence ч=hc/E2-E1=6.7*10^-7 m 6-Ma fhemet chi menna sry bass ma fiyeh a3tik jaweb w manne fehim el sou2al J I’m French educated The bonus part depends on (6) Sry again Cheers
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#26 | |
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Quote:
the last part is very easy: 1st u're asked to check that no atom overpasses E5 when hit by 4eV and starting at ground state. just add -5.39 + 4 = -1.39eV which is between -1.04eV and -1.51eV so between E5 and E6. hence it will not overpass E5... and the bonus builds on this same idea: when u hit it with 4eV, due to the 'quantization' thing, it will only use 3.88eV (=5.39-1.51) to jump from E1 to E5. the remaining 4-3.88=0.12eV will go into kinetic energy (energie cinetique) cheers & good luck to everyone... |
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#27 | |
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AM here to help any one brevet
but am not sure iza fi any brevet IF any questions ana 7ader..... ![]() Quote:
Last edited by MARX ®; 06-09-2008 at 07:52 AM. |
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#28 |
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I can help with physics, specially with the "mechanique and electrecite" parts
HOWDY |
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#29 |
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guys i'll help you to ......fail the exams,
just watch all the Euro 2008 matches, share your opinions abt it in Vz
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the Hell is empty...all Devils are here ...
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#30 |
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I can help bio SV spc bel part hereditaire ou genetique et Immuno (li man yahoumouhou l amr)
![]() Gd luck again
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| The Following User Says Thank You to No One For This Useful Post: | TAREK® (06-09-2008) |
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