MATHS riddle

[J()e]

Here is the solution

Why it is impossible here it goes:

as we said everyday we must kill a number impair(mefrid)of cows

and we know enno impair+impair=pair for example(3+3=6 6=pair while 3=impair,7+7=14 etc....)

so in every 2 days we have a number pair of cows that are going to die
in 4 days we have also a number pair
but in the 5th day we have an impair number while the number desired to be reached is 30 wich is pair cause 30 can be divided by 2


Cheers

[duce]

joe the sum of 5 odd numbers MUST be an odd number
(2n+1)*5 = 10n+5. knowing 10n is even(multiple of 2), and adding 5, we can tell that the result is odd.
starting from the fact that 0 is not an odd number, you cannot have 5 odd numbers who sum up to 30. i dunno why u guys even tried finding the answer

[Sogelec]

Tayeb Tayeb inta w yeh yala more riddles,shu ba3mel i 4got skool days

[duce]

i wanna know abt my answer to alias' riddle! i sent him a pm a while ago. mafroud enno i got it right!

[ALIAS]

sorry i didn't reply sooner
my internet was down... but now it is working again

duce and crystal soul got it right

the answer is:
5 cigs
how?
well he has 10
10= 9+1
from the 9 he makes 3 cigs
he smokes them and each cig produces a leftover
now he has 3(from smoked cigs) and 1(from the original 10)
so with the 3 he makes a cig and smokes it and so he get another leftover
so now he has 2
he borrows 1 from his friend
now he has 3
he makes them a cig and smoke it and get from it 1 leftover
so he returns it to his friend

[J()e]

yalla more riddles guyz...try to post here

we need riddles to solve

[J()e]

here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....

[Sogelec]

Originally Posted by J()e

here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....

The Time when 1 of them return byen7asab mn l 17 minutes?

[J()e]

of course....

it's easy yalla

PS:if for example the 2nd and the 1st crossed the bridge bten7asab 2 mins Raw7a.

[abousoun]

Originally Posted by ALIAS

abousoun gest it 90% right
he got the total rights but he made 1 mistake he broke the second rulebass bi tari2a gher moubashara - yemkem el rule ma kenet wad7a mazbout)

he can only borrow one (and only one) from one friend (only one friend) (i think it is clear now)
i will post the solution tomorrow noon unless you want more time to think about it

you said frist borrow one cigarette from a friend, not one cigarette from one friend ... heik byi5telif, otherwise why he would have many friends in this ridle, one friend bzyede

Originally Posted by J()o

here is one not hard medium level riddle

we have a bridge...and 4 people wants to pass this bridge....

the 1st one needs 1 min
the 2nd one needs 2 mins
the 3rd one needs 5 mins
the 4th one needs 10 mins

haida wa2et only raw7a...

and they must go 2 people at the same time and one of the is obliged to get back ..

how can all of the 4 people cross the bridge in 17 mins ....

PM sent, w concerning your previous riddle ... there was no connection to send the answer

Thank You ...