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#71 |
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okey since i'm having several questions about if there is le3eb 3al kalem in the last riddle ...
I can assure you there is no le3eb 3al kalem ... el solution is purely mathematical ... w ignore the sentence "ma3 eno 7a2on mish hal2ad bass ma3rouf 3an enigma eno karime " iza kenit 3am tday3kon it's just for fun i put it ![]() Thank You ...
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#72 |
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I think we must know how many bananas each one ate...
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#73 |
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enigma first one to solve the last riddle ... tabi3e ta3rifa ... def3a min jaybita
![]() Thank You ...
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I think you should figure that out from the given (donnée en francais
)Thank You ...
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#76 | |
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in the meantime i'll post a riddle similar to J()e's first riddle : you have 4 numbers : 2,4,6,8 Using these numbers , together with the operations (+) , (−) , (×) , and (÷) how can you reach the value of 25 ... each number must be used once only, and you don't have to use +,-,X,/ all of them Thank You ...
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chou el chabibe ? wein el math geeks ? Thank You ...
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Sweets_HsN the second one to solve the bananas riddle
![]() Thank You ...
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okey so we have 3 peoples with 8 bananas all of them ate equally so simply each one ate 8/3 of bananas ya3ne kel wa7ad akal 2 bananas + 2/3 of a banana the first one (Sweets_HsN) had 5 and he ate 2 + 2/3 the second one (J()e) had 3 and he ate 2 + 2/3 ya3ne first one gave enigma [5 - (2+2/3)] = 2 + 1/3 and the second one gave enigma [3 - (2+2/3)] = 1/3 heik enigma betkoun akalit 2 + 1/3+ 1/3 = 2 + 2/3 the same as both let's consider 1/3 = x (where x is the amount of banana J()e gave enigma) so J()e gave enigma x and Sweets_HsN gave enigma 2 + 1/3 = 7x x + 7x = 8000 so 8x=8000 so x = 1000 ya3ne J()e lezim ye5od 1000 L.L w sweets_HsN 7000 L.L Thank You ...
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[(2/8)+6]*4 = 25 Thank You ...
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